In the given molecules the sites undergoes deprotonation and protonation most readily respectively are x & y the x+y=?
`overset(1)(N_(2)H)-underset(""^(2)NH)underset(||)C-overset(3)(NH)-CH_(2)-CH_(2)-CH_(2)-underset(""^(4)NH_(2))underset(|)CH-overset(5)(COOH)`

Answer

To solve the problem, we need to identify the sites in the given molecule that undergo deprotonation and protonation most readily. Let's break it down step by step.

### Step 1: Analyze the Structure
The given molecule can be represented as follows:
- **1**: \( NH_2 \)
- **2**: \( C \) (double bond with \( NH \))
- **3**: \( NH \)
- **4**: \( CH_2 \)
- **5**: \( CH_2 \)
- **6**: \( CH_2 \)
- **7**: \( CH \)
- **8**: \( COOH \)

### Step 2: Identify the Site for Deprotonation (x)
Deprotonation typically occurs at acidic sites, which in organic molecules are usually carboxylic acids or other acidic hydrogens. In this case, the carboxylic acid group \( COOH \) is present at position 5.

- **Deprotonation**: The hydrogen from the carboxylic acid (\( COOH \)) can be removed, resulting in a negatively charged carboxylate ion (\( COO^- \)).

Thus, the site that undergoes deprotonation most readily is at position **5**.

### Step 3: Identify the Site for Protonation (y)
Protonation occurs at basic sites, which are typically nitrogen atoms with lone pairs that can accept a proton. In the given structure, we have several nitrogen atoms:

- The nitrogen at position 2 is part of a double bond and has a lone pair that can participate in resonance.
- The nitrogen at position 3 is \( NH \) and can also accept a proton.
- The nitrogen at position 1 is \( NH_2 \) and is sp3 hybridized, making it less basic compared to sp2 nitrogen.

Among these, the nitrogen at position **2** is sp2 hybridized and is more basic due to its ability to stabilize the positive charge after protonation.

Thus, the site that undergoes protonation most readily is at position **2**.

### Step 4: Calculate x + y
Now that we have identified:
- \( x = 5 \) (deprotonation at position 5)
- \( y = 2 \) (protonation at position 2)

We can calculate:
\[ x + y = 5 + 2 = 7 \]

### Final Answer
The value of \( x + y \) is **7**.

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