Which statement is correct about photochemical bromination of Butane ?
`CH_3-CH_2-CH_2-CH_3overset(Br_2,h upsilon)to`

Options

A. 1-Bromobutane and 2-Bromobutanes are formed in equal amounts.
B. 2-Bromobutane is formed with faster rate than 2-chlorobutane in the other experiment of chlorination.
C. The major product is an equimolar mixture of two compounds.
D. Major product is formed by more stable carbocation.

Answer

To solve the question regarding the photochemical bromination of butane, we will analyze the process step by step.

### Step 1: Understand the Reaction
Photochemical bromination of butane involves the reaction of butane (C₄H₁₀) with bromine (Br₂) in the presence of light (hν). This reaction proceeds through a free radical mechanism.

### Step 2: Mechanism of Bromination
1. **Initiation**: The reaction begins with the homolytic cleavage of the Br-Br bond under the influence of light, generating two bromine radicals:
\[ \text{Br}_2 \xrightarrow{h\nu} 2 \text{Br}^\cdot \]

2. **Propagation**: The bromine radical can then abstract a hydrogen atom from butane, forming a butyl radical and HBr:
\[ \text{Br}^\cdot + \text{C}_4\text{H}_{10} \rightarrow \text{C}_4\text{H}_9^\cdot + \text{HBr} \]
The butyl radical can be either a primary (1°) or secondary (2°) radical depending on which hydrogen is abstracted.

3. **Formation of Products**: The butyl radical can then react with another bromine radical to form brominated butane:
\[ \text{C}_4\text{H}_9^\cdot + \text{Br}^\cdot \rightarrow \text{C}_4\text{H}_9\text{Br} \]

### Step 3: Identify the Types of Radicals
- **Primary Radical**: Formed when a hydrogen is removed from a terminal carbon (less stable).
- **Secondary Radical**: Formed when a hydrogen is removed from a carbon that is attached to two other carbons (more stable).

### Step 4: Analyze the Products
The bromination of butane will yield:
- 1-bromobutane (from the primary radical)
- 2-bromobutane (from the secondary radical)

Due to the stability of the secondary radical, 2-bromobutane will be formed in greater amounts compared to 1-bromobutane.

### Step 5: Conclusion
The major product of the photochemical bromination of butane is an equimolar mixture of 1-bromobutane and 2-bromobutane, but since 2-bromobutane is more stable, it will be the predominant product.

### Final Answer
The correct statement about the photochemical bromination of butane is:
- The major product is an equimolar mixture of two compounds (1-bromobutane and 2-bromobutane).