In the reaction of chlorine with propene at `450^@C`, the major product is

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Answer

To determine the major product of the reaction between chlorine and propene at 450°C, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are chlorine (Cl₂) and propene (C₃H₆). Propene has the structure CH₃-CH=CH₂.

### Step 2: Understand the Reaction Conditions
The reaction is taking place at a high temperature of 450°C. At elevated temperatures, the nature of the reaction can change compared to reactions at lower temperatures.

### Step 3: Determine the Type of Reaction
At lower temperatures, the reaction between chlorine and propene typically leads to a substitution reaction, where chlorine atoms replace hydrogen atoms in the propene molecule. However, at higher temperatures, like 450°C, the reaction is more likely to favor addition reactions rather than substitution.

### Step 4: Predict the Major Product
Given the high temperature, the major product will be formed through an addition reaction. The chlorine molecule (Cl₂) adds across the double bond of propene. The double bond between the second and third carbon atoms opens up, allowing the chlorine atoms to attach to the carbon atoms.

The addition of Cl₂ to propene results in the formation of 1,2-dichloropropane, which has the structure:
- Cl-CH₂-CH(CH₃)-CH₂Cl

### Step 5: Conclusion
Thus, the major product of the reaction of chlorine with propene at 450°C is 1,2-dichloropropane.

### Final Answer:
The major product is 1,2-dichloropropane.

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