The reagent system for preparing propan-1-ol from propene is :-

Options

A. `Hg(O Ac)_2//H_2O` followed by `NaBH_4`
B. `H_2SO_4//H_2O`
C. `B_2H_6` followed by `H_2O_2`
D. `HCO_2H//H_2SO_4`

Answer

To prepare propan-1-ol from propene, we can use the hydroboration-oxidation method. Here’s a step-by-step explanation of the process:

### Step-by-Step Solution:

1. **Identify the Reactant:**
- The starting material is propene (C3H6), which has the structure:
\[ \text{CH}_3-\text{CH}=\text{CH}_2 \]

2. **Select the Reagent System:**
- The reagent system for hydroboration-oxidation consists of:
- **Boron Hydride (B2H6)** for hydroboration.
- **Hydrogen Peroxide (H2O2)** in a basic medium for oxidation.

3. **Hydroboration Reaction:**
- In the hydroboration step, B2H6 adds across the double bond of propene. This reaction follows the anti-Markovnikov rule, meaning that the boron atom will attach to the less substituted carbon (the one with more hydrogen atoms).
- The product of this step is:
\[ \text{CH}_3-\text{CH}_2-\text{B(OH)}_2 \]
- This intermediate is called trialkyl borane.

4. **Oxidation Reaction:**
- In the oxidation step, the trialkyl borane is treated with hydrogen peroxide (H2O2) in a basic medium (usually NaOH).
- This converts the boron atom into a hydroxyl group (-OH), resulting in the formation of propan-1-ol:
\[ \text{CH}_3-\text{CH}_2-\text{OH} \]
- The final product is propan-1-ol (C3H8O).

### Final Answer:
The reagent system for preparing propan-1-ol from propene is **B2H6 followed by H2O2 in a basic medium**.

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