In which reaction incorrect products have been reported.

Options

A. `CH_2=CH-CHO overset(HCl(g)(-10^@C))to undersetunderset(Cl)(|)CH_2-CH_2-CHO`
B. `CH_2=CH-COOH overset(H_2O // H_2SO_4)to undersetunderset(OH)(|)CH_2-CH_2-COOH`
C. `CH_3-oversetoverset(CH_3)(|)C=CH-undersetunderset(O)(||)C-CH_3overset(CH_3OH//H_2SO_4)to CH_3-oversetoverset(CH_3)(|)CH-undersetunderset(OCH_3)(|)CH-undersetunderset(O)(||)C-CH_3`
D. `CH_3-CH=CH-OCH_3overset(CH_3OH//H^+)toCH_3-CH_2-undersetunderset(OCH_3)(|)CH-OCH_3`

Explanation

To determine in which reaction incorrect products have been reported, let's analyze each reaction step by step.

### Step 1: Analyze the First Reaction
**Reaction:** CH2=CHOH + HCl

1. **Protonation:** The double bond attacks the H+ from HCl, leading to the formation of a carbocation.
2. **Intermediate Formation:** The carbocation is CH2+CH(OH).
3. **Nucleophilic Attack:** Cl- attacks the carbocation, resulting in CH2Cl-CH(OH).
4. **Rearrangement:** The product rearranges to form CH2Cl-CH2-C(=OH) (alcohol).

**Conclusion:** The product is correct.

### Step 2: Analyze the Second Reaction
**Reaction:** CH2=CHC(=OH) + H2O

1. **Nucleophilic Attack:** Water attacks the double bond, leading to the formation of an alcohol.
2. **Intermediate Formation:** The intermediate is CH2(OH)-CH(OH)-C(=OH).
3. **Rearrangement:** The product rearranges to form CH2(OH)-CH2-C(=OH).

**Conclusion:** The product is correct.

### Step 3: Analyze the Third Reaction
**Reaction:** CH3-CH=CH-CH(=OH)-CH3

1. **Protonation:** The double bond is protonated, forming a carbocation.
2. **Intermediate Formation:** The carbocation is CH3-CH+-CH(OH)-CH3.
3. **Nucleophilic Attack:** Methanol attacks the carbocation, leading to CH3-CO-CH3-CH(OH).
4. **Rearrangement:** The product rearranges, but here the structure does not lead to a stable product.

**Conclusion:** The product is incorrect.

### Step 4: Analyze the Fourth Reaction
**Reaction:** CH3-CH2-CH(OH)-CH3

1. **Carbocation Formation:** The hydroxyl group stabilizes the carbocation.
2. **Nucleophilic Attack:** The methanol attacks the carbocation, leading to CH3-CH2-CH(OH)-CH3.
3. **Final Product:** The product formed is stable.

**Conclusion:** The product is correct.

### Final Conclusion
The incorrect product is from the **third reaction** (option C).

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