In which of the following reactions and products are correctly matched ?

Options

A. `F_3C-CH=CH_2+HCl to F_3C-undersetunderset(Cl)(|)CH-CH_3`
B. `CH_3-CH=CH-oversetoverset(O)(||)C-OCH_3+IC l to CH_3-undersetunderset(Cl)(|)CH-undersetunderset(I)(|)CH-oversetoverset(O)(||)C-OCH_3`
C. `C_6H_5CH=CHCH_3+HBr overset(ROOR)to C_6H_5CH_2-undersetunderset(Br)(|)CH-CH_3`
D.

Answer

To determine which of the given reactions and products are correctly matched, we will analyze each reaction step by step.

### Step 1: Analyze Reaction 1
**Reaction:** CF3 CH=CH2 + HCl
**Expected Product:** CF3 CHCl CH2

- The CF3 group is a strong electron-withdrawing group. When HCl adds to the alkene, the alkene will preferentially attack from the side that leads to the more stable carbocation.
- If the alkene attacks from the right side (CH2), a secondary carbocation is formed, which is destabilized by the CF3 group. Instead, the attack occurs from the left side (CF3 CH), leading to a primary carbocation.
- The product formed will be CF3 CH2 CH2Cl, which is different from the expected product.

**Conclusion:** This reaction is incorrectly matched.

### Step 2: Analyze Reaction 2
**Reaction:** CH3 CH=CH + ICl
**Expected Product:** CH3 CHCl CHI

- In this reaction, the alkene will attack the iodine, forming a more stable carbocation.
- The iodine is less electronegative than chlorine and acts as the electrophile. The product formed will be CH3 CHCl CHI, which matches the expected product.

**Conclusion:** This reaction is correctly matched.

### Step 3: Analyze Reaction 3
**Reaction:** C6H5 CH=CH3 + HBr (with peroxide)
**Expected Product:** C6H5 CH2 CHBr

- The presence of peroxide indicates a radical mechanism. The HBr will add to the alkene to form a benzyl radical.
- The radical will stabilize, and the final product will be C6H5 CH2 CHBr, which matches the expected product.

**Conclusion:** This reaction is correctly matched.

### Step 4: Analyze Reaction 4
**Reaction:** Phenylbutadiene + HCl (with ROOR)
**Expected Product:** 1-chloro-2-phenylbutane

- In this radical reaction, the chlorine radical will add to the alkene, forming a radical that can stabilize through resonance.
- However, the expected product indicates a chlorine at the second position, which is incorrect because the radical will stabilize at the first position instead.

**Conclusion:** This reaction is incorrectly matched.

### Final Conclusion:
The correctly matched reactions are:
- **Reaction 2:** CH3 CH=CH + ICl → CH3 CHCl CHI (Correct)
- **Reaction 3:** C6H5 CH=CH3 + HBr (with peroxide) → C6H5 CH2 CHBr (Correct)

### Summary of Correct Matches:
- **Correct Matches:** Reaction 2 and Reaction 3
- **Incorrect Matches:** Reaction 1 and Reaction 4