`PhSO_2CH_2-CH_2-OMeunderset(EtOD) overset(EtO^(theta))to"product"+underset("(recovered reactant)")(PhSO_2-oversetoverset(D)(|)CH-CH_2OMe`.
The product is :

Options

A. `PhSO_2CH=CH_2`
B. `CH_2=CH-O Me`
C. `PhSO_2CH_2-CD_2OMe`
D. `CD_2=CH_2`

Explanation

To solve the problem, we need to analyze the reaction of the compound PhSO₂CH₂CH₂OMe with EtO⁻ in the presence of EtOD. Let's break down the reaction step by step.

### Step 1: Identify the Structure
The starting compound can be represented as PhSO₂-CH₂-CH₂-OMe. Here, Ph represents a phenyl group (C₆H₅), SO₂ is a sulfonyl group, and OMe is a methoxy group (–OCH₃).

### Step 2: Deprotonation
The base EtO⁻ (ethoxide ion) will act to deprotonate the most acidic hydrogen in the molecule. In this case, the hydrogen on the CH₂ adjacent to the sulfonyl group (PhSO₂) is the most acidic due to the electron-withdrawing effect of the sulfonyl group.

The reaction can be represented as:
\[ \text{PhSO}_2\text{-CH}_2\text{-CH}_2\text{-OMe} + \text{EtO}^- \rightarrow \text{PhSO}_2\text{-C}^- \text{H}\text{-CH}_2\text{-OMe} + \text{EtOH} \]

### Step 3: Formation of the Carbanion
After deprotonation, we form a carbanion at the carbon adjacent to the sulfonyl group:
\[ \text{PhSO}_2\text{-C}^- \text{H}\text{-CH}_2\text{-OMe} \]

### Step 4: Resonance Stabilization
The carbanion formed is resonance-stabilized by the sulfonyl group. This stabilization allows the negative charge to delocalize, making the carbanion more stable.

### Step 5: Elimination Reaction
The next step involves the elimination of the methoxy group (–OMe) as a leaving group. The carbanion can form a double bond with the adjacent carbon, leading to the formation of an alkene. The reaction can be represented as:
\[ \text{PhSO}_2\text{-C}^- \text{H}\text{-CH}_2\text{-OMe} \rightarrow \text{PhSO}_2\text{-C}=\text{CH}_2 + \text{OMe}^- \]

### Step 6: Final Product
The final product will be:
\[ \text{PhSO}_2\text{-C}=\text{CH}_2 \]
This product is a vinyl sulfone where the sulfonyl group is attached to a double-bonded carbon.

### Summary of the Reaction
The overall reaction can be summarized as:
\[ \text{PhSO}_2\text{-CH}_2\text{-CH}_2\text{-OMe} + \text{EtO}^- \rightarrow \text{PhSO}_2\text{-C}=\text{CH}_2 + \text{OMe}^- + \text{EtOH} \]