`CH_2Ounderset(H_3O^(o+))overset(CHD_2MgI)toX underset(Delta)overset(Conc.H_2SO_4)toY`
In the above reaction compound X & Y respectively will be

Options

A. `oversetoverset(OH)(|)CHD-CH_2-OH,CHO-CHO`
B. `CHD_2-CH_2-OH, CHO-CHO`
C. `CHD_2-CH_2-OH, CD_2=CH_2`
D. `undersetunderset(OH)(|)CHD-CH_2-OH,CD_2=CD_2`

Explanation

To solve the given reaction step by step, let's analyze the transformation of formaldehyde (CH₂O) through the Grignard reagent (CHD₂MgI) and then through concentrated sulfuric acid.

### Step 1: Reaction of Formaldehyde with Grignard Reagent
1. **Identify the Reactants**: The starting compound is formaldehyde (CH₂O) and the Grignard reagent is CHD₂MgI.
2. **Nucleophilic Attack**: The nucleophile (CHD₂⁻) from the Grignard reagent attacks the electrophilic carbon of the carbonyl group (C=O) in formaldehyde. This results in the breaking of the double bond and the formation of an alkoxide intermediate.
- **Intermediate Structure**: The structure after the nucleophilic attack will be:
- O⁻ (alkoxide) attached to the carbon, which is also attached to a hydrogen (H) and a CHD₂ group.
3. **Formation of Alkoxide**: The alkoxide (O⁻) will then react with the magnesium ion (MgI⁺) from the Grignard reagent, leading to the formation of:
- CH₂(OH)CHD₂MgI

### Step 2: Protonation of the Alkoxide
1. **Reaction with Acid**: The alkoxide (CH₂(OH)CHD₂⁻) is then treated with H₃O⁺ (acid), which protonates the oxygen atom.
2. **Final Product (X)**: After protonation, the product will be:
- CH₂(OH)CHD₂
- This compound is an alcohol where the OH group is attached to the carbon that was originally part of the carbonyl group of formaldehyde.

### Step 3: Dehydration with Concentrated Sulfuric Acid
1. **Reaction with Concentrated H₂SO₄**: The alcohol (CH₂(OH)CHD₂) is treated with concentrated sulfuric acid (H₂SO₄) and heated. This is a dehydration reaction where water (H₂O) is eliminated.
2. **Formation of Alkene (Y)**: The elimination of water leads to the formation of a double bond between the two carbon atoms:
- The resulting product will be:
- CH₂=CHD₂
- This compound is an alkene.

### Summary of Products
- **Compound X**: CH₂(OH)CHD₂ (an alcohol)
- **Compound Y**: CH₂=CHD₂ (an alkene)

### Final Answer
- The compounds X and Y are:
- **X**: CH₂(OH)CHD₂
- **Y**: CH₂=CHD₂