`CH_(3)CONH_(2) overset(H_(3)O^(+))rarr` Product is :

Answer

To determine the product of the reaction between acetamide (CH₃CONH₂) and hydronium ion (H₃O⁺), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are acetamide (CH₃CONH₂) and hydronium ion (H₃O⁺). Acetamide is an amide, which contains a carbonyl group (C=O) bonded to a nitrogen atom (N).

### Step 2: Understand the Reaction Type
The reaction involves an acid-base interaction where H₃O⁺ (the hydronium ion) acts as a strong acid. Acetamide can be protonated by the hydronium ion.

### Step 3: Protonation of Acetamide
When acetamide is protonated by H₃O⁺, the nitrogen atom in the amide group gains a proton (H⁺), leading to the formation of an ammonium ion (CH₃CONH₃⁺).

### Step 4: Hydrolysis of the Ammonium Ion
The protonated acetamide (CH₃CONH₃⁺) can undergo hydrolysis. The presence of water (from the hydronium ion) facilitates the cleavage of the C-N bond. This results in the formation of acetic acid (CH₃COOH) and ammonia (NH₃).

### Step 5: Write the Products
The products of the reaction are:
1. Acetic acid (CH₃COOH)
2. Ammonia (NH₃)

### Final Answer
Thus, the product of the reaction between acetamide and hydronium ion is acetic acid (CH₃COOH) along with the liberation of ammonia gas (NH₃).

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