On passing `SO_3` gas through `CS_2`, it produces

Answer

To solve the question regarding the reaction of sulfur trioxide (SO₃) gas with carbon disulfide (CS₂), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are sulfur trioxide (SO₃) and carbon disulfide (CS₂).

2. **Understand the Reaction**:
- When SO₃ gas is passed through CS₂, a chemical reaction occurs. This reaction leads to the formation of new products.

3. **Write the Chemical Equation**:
- The reaction can be represented as:
\[ \text{CS}_2 + \text{SO}_3 \rightarrow \text{COS} + \text{SO}_2 \]
- Here, carbon disulfide (CS₂) reacts with sulfur trioxide (SO₃) to produce carbonyl sulfide (COS) and sulfur dioxide (SO₂).

4. **Balance the Reaction**:
- To ensure the law of conservation of mass is followed, we need to check if the equation is balanced.
- The balanced equation is:
\[ \text{CS}_2 + 3\text{SO}_3 \rightarrow \text{COS} + 2\text{SO}_2 \]
- This indicates that one molecule of carbon disulfide reacts with three molecules of sulfur trioxide to produce one molecule of carbonyl sulfide and two molecules of sulfur dioxide.

5. **Identify the Products**:
- The products formed from the reaction are carbonyl sulfide (COS) and sulfur dioxide (SO₂).

### Final Answer:
On passing sulfur trioxide (SO₃) gas through carbon disulfide (CS₂), it produces carbonyl sulfide (COS) and sulfur dioxide (SO₂).

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