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Oxidation state exhibited by Cl in HClO(...

Oxidation state exhibited by Cl in `HClO_(2)` is

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To determine the oxidation state of chlorine (Cl) in the compound HClO₂, we can follow these steps: ### Step 1: Identify the known oxidation states - The oxidation state of hydrogen (H) is +1. - The oxidation state of oxygen (O) is typically -2. ### Step 2: Write the formula for the oxidation state In the compound HClO₂, we can express the sum of the oxidation states as follows: \[ \text{Oxidation state of H} + \text{Oxidation state of Cl} + 2 \times \text{Oxidation state of O} = 0 \] ### Step 3: Substitute the known values Substituting the known oxidation states into the equation: \[ (+1) + X + 2 \times (-2) = 0 \] Where \(X\) is the oxidation state of chlorine. ### Step 4: Simplify the equation Now, simplify the equation: \[ 1 + X - 4 = 0 \] ### Step 5: Solve for X Rearranging the equation gives: \[ X - 3 = 0 \] Thus, \[ X = +3 \] ### Conclusion The oxidation state of chlorine in HClO₂ is +3. ---
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Assertion: HClO_(4) is a stronger acid than HClO_(3) . Reason: Oxidation state of Cl in HClO_(4) is +VII and in HClO_(3)+V .