Molecular formula `C_(3)H_(6)O_(2)` have two structure A and B . Structure A releases `CO_(2)` gas with `NaHCO_(3)` but B does not. Compound B is fruily smelling liquid. Write the structure & IUPAC name of A and B

Answer

To solve the problem, we need to identify two compounds with the molecular formula C3H6O2: compound A, which releases CO2 gas with NaHCO3, and compound B, which is a fruity-smelling liquid.

### Step-by-Step Solution:

1. **Identify Compound A**:
- The fact that compound A releases CO2 gas when reacted with sodium bicarbonate (NaHCO3) indicates that it is likely a carboxylic acid. Carboxylic acids react with bicarbonates to produce carbon dioxide.
- Given the molecular formula C3H6O2, we can deduce that compound A must have three carbon atoms. The simplest carboxylic acid with three carbons is propanoic acid.

**Structure of Compound A**:
- The structure of propanoic acid can be represented as:
```
CH3-CH2-COOH
```

**IUPAC Name of Compound A**:
- The IUPAC name of this structure is **Propanoic Acid**.

2. **Identify Compound B**:
- Compound B does not release CO2 when reacted with NaHCO3, which suggests that it is not an acid. Additionally, it is described as a fruity-smelling liquid, indicating that it is likely an ester.
- Since we are still working with the molecular formula C3H6O2, the simplest ester that can be formed from propanoic acid is methyl acetate.

**Structure of Compound B**:
- The structure of methyl acetate can be represented as:
```
CH3-COO-CH3
```

**IUPAC Name of Compound B**:
- The IUPAC name of this structure is **Methyl Acetate**.

### Final Answer:
- **Compound A**:
- Structure: CH3-CH2-COOH
- IUPAC Name: Propanoic Acid
- **Compound B**:
- Structure: CH3-COO-CH3
- IUPAC Name: Methyl Acetate