A compound (P) on reaction with "Q" in basic medium (KOH) gives a bad smelling compound `(CH_(3)CH_(2)NC)`. Compound Q can be prepare by reaction with calcium hypochlorite `[Ca(O Cl)_(2)]` P and Q can :

Options

A. `CH_(3)-CH_(2)-NH_(2) & CHCl_(3)`
B. `CH_(3)-CH_(2)-NO_(2) & CH_(3)Cl`
C. `CH_(3)-CH_(2)-NH-CH_(3) & COCl_(2)`
D. `(CH_(3)-CH_(2))_(3)N & Cl_(2)`

Explanation

To solve the problem, we need to identify the compounds P and Q based on the information provided. Let's break down the steps:

### Step 1: Identify Compound Q
1. **Understanding the Reaction**: Compound Q is prepared by reacting calcium hypochlorite (Ca(OCl)₂) with water. This reaction produces chlorine gas (Cl₂) and calcium hydroxide (Ca(OH)₂).
2. **Hydrolysis of Calcium Hypochlorite**:
\[ \text{Ca(OCl)}_2 + \text{H}_2\text{O} \rightarrow \text{Cl}_2 + \text{Ca(OH)}_2 \]
3. **Chlorination of Ethanol**: The chlorine gas can react with ethanol (C₂H₅OH) in the presence of calcium hydroxide to form chloroform (CHCl₃).
4. **Final Compound Q**: After the chlorination process, we find that compound Q is chloroform (CHCl₃).

### Step 2: Identify Compound P
1. **Understanding the Reaction with Q**: We know that compound P reacts with chloroform (Q) in a basic medium (KOH) to produce a bad-smelling compound, which is ethyl isocyanide (CH₃CH₂NC).
2. **Reaction of Ethyl Amine with Chloroform**: The compound P that reacts with chloroform is ethyl amine (C₂H₅NH₂).
3. **Reaction Equation**:
\[ \text{C}_2\text{H}_5\text{NH}_2 + \text{CHCl}_3 + \text{KOH} \rightarrow \text{C}_2\text{H}_5\text{NC} + \text{KCl} + \text{H}_2\text{O} \]
Here, ethyl amine reacts with chloroform in the presence of KOH to yield ethyl isocyanide.

### Conclusion
- **Compound P**: Ethyl amine (C₂H₅NH₂)
- **Compound Q**: Chloroform (CHCl₃)

### Final Answer
- P is ethyl amine (C₂H₅NH₂)
- Q is chloroform (CHCl₃)