The percentage composition of the elements of `C_(8)H_(9)ON` is

Options

A. 8:9:1:1
B. 76.8:7.2:12.8:11.2
C. 12:1:16:14
D. none of these

Answer

To find the percentage composition of the elements in the compound \( C_8H_9ON \), we will follow these steps:

### Step 1: Calculate the Molecular Mass
The molecular formula is \( C_8H_9ON \). We will calculate the molecular mass by summing the atomic masses of each element multiplied by their respective number of atoms.

- Carbon (C): 12 g/mol
- Hydrogen (H): 1 g/mol
- Oxygen (O): 16 g/mol
- Nitrogen (N): 14 g/mol

Now, we calculate the total molecular mass:

\[ \text{Molecular Mass} = (12 \times 8) + (1 \times 9) + (16 \times 1) + (14 \times 1) \]

Calculating each term:

- Carbon: \( 12 \times 8 = 96 \)
- Hydrogen: \( 1 \times 9 = 9 \)
- Oxygen: \( 16 \times 1 = 16 \)
- Nitrogen: \( 14 \times 1 = 14 \)

Now summing these values:

\[ \text{Molecular Mass} = 96 + 9 + 16 + 14 = 135 \text{ g/mol} \]

### Step 2: Calculate the Percentage Composition of Each Element

**Percentage of Carbon (C)**:
\[ \text{Percentage of C} = \left( \frac{96}{135} \right) \times 100 = 71.11\% \]

**Percentage of Hydrogen (H)**:
\[ \text{Percentage of H} = \left( \frac{9}{135} \right) \times 100 = 6.67\% \]

**Percentage of Oxygen (O)**:
\[ \text{Percentage of O} = \left( \frac{16}{135} \right) \times 100 = 11.85\% \]

**Percentage of Nitrogen (N)**:
\[ \text{Percentage of N} = \left( \frac{14}{135} \right) \times 100 = 10.37\% \]

### Step 3: Summarize the Results
Now we can summarize the percentage composition of each element in the compound \( C_8H_9ON \):

- Carbon (C): 71.11%
- Hydrogen (H): 6.67%
- Oxygen (O): 11.85%
- Nitrogen (N): 10.37%

### Final Answer
The percentage composition of the elements in \( C_8H_9ON \) is approximately:
- C: 71.11%
- H: 6.67%
- O: 11.85%
- N: 10.37%