An element crystallises as face-centred cubic lattice with density as `5.20 g//cm^(3)` and edge length of the side of unit cell as 300pm. Calculate mass of the element which contains `3.01 xx 10^(24)` atoms

Explanation

To solve the problem step-by-step, we will follow the given information and apply the relevant formulas.

### Step 1: Understand the FCC Structure
In a face-centered cubic (FCC) lattice, the number of atoms per unit cell (Z) is calculated as follows:
- There are 8 corner atoms, each contributing \( \frac{1}{8} \) of an atom to the unit cell.
- There are 6 face-centered atoms, each contributing \( \frac{1}{2} \) of an atom to the unit cell.

Calculating Z:
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