In AgBr, there can occur

Options

A. only schottky defect
B. only Frenkel defect
C. both (1) and (2)
D. None of these

Explanation

To solve the question regarding defects in AgBr, we will analyze the types of defects that can occur in ionic solids, specifically focusing on Schottky and Frenkel defects.

### Step-by-Step Solution:

1. **Identify the Nature of AgBr**:
- AgBr is an ionic compound composed of Ag⁺ (silver cation) and Br⁻ (bromide anion).
- Since it is an ionic solid, it can exhibit ionic defects.

**Hint**: Remember that only ionic solids can exhibit Schottky and Frenkel defects.

2. **Understand Schottky Defect**:
- A Schottky defect occurs when an equal number of cations and anions are missing from the crystal lattice.
- This defect maintains the electrical neutrality of the crystal because the number of positive charges lost (cations) is equal to the number of negative charges lost (anions).

**Hint**: Schottky defects involve missing pairs of ions.

3. **Understand Frenkel Defect**:
- A Frenkel defect occurs when a cation (or anion) leaves its original lattice site and occupies an interstitial site, creating a vacancy at its original position.
- This defect also maintains electrical neutrality since one ion moves while another vacancy is created.

**Hint**: Frenkel defects involve an ion moving to a different position within the lattice.

4. **Determine the Possible Defects in AgBr**:
- Since AgBr is an ionic compound, it can exhibit both types of defects: Schottky and Frenkel.
- Therefore, both defects can occur in AgBr.

**Hint**: Consider the definitions of both defects and how they apply to the ionic structure of AgBr.

5. **Conclusion**:
- The correct answer to the question is that AgBr can exhibit both Schottky and Frenkel defects.

**Final Answer**: AgBr can show both types of defects, so the correct option is **option 3** (both 1 and 2).