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S(1): Distance between Na^(+) " & " Cl^(...

`S_(1)`: Distance between `Na^(+) " & " Cl^(-)` in NaCl crystal is more than half of edge length.
`S_(2)`: The no. of triangular viods in the given arrangement in the enclosed region is 3

`S_(3)`: In ZnS structure, `2Zn^(2+) " & " 2S^(2-)` ions are present in each unit cell

A

FFT

B

FTF

C

TFF

D

FFF

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will evaluate each statement step by step. ### Step 1: Evaluate Statement S1 **Statement S1**: "Distance between Na⁺ and Cl⁻ in NaCl crystal is more than half of edge length." 1. **Understanding the NaCl Structure**: In a NaCl crystal, the Na⁺ and Cl⁻ ions are arranged in a face-centered cubic (FCC) lattice. The edge length of the unit cell (a) is related to the ionic radii of Na⁺ and Cl⁻. 2. **Distance Calculation**: The distance between Na⁺ and Cl⁻ ions in the NaCl crystal is equal to the sum of their ionic radii (r_Na + r_Cl). 3. **Comparison with Edge Length**: The edge length (a) of the NaCl unit cell is equal to 2(r_Na + r_Cl). Therefore, the distance between Na⁺ and Cl⁻ is actually less than half of the edge length (a/2). 4. **Conclusion**: Thus, this statement is **false**. ### Step 2: Evaluate Statement S2 **Statement S2**: "The number of triangular voids in the given arrangement in the enclosed region is 3." 1. **Understanding Triangular Voids**: In a close-packed arrangement of spheres (like in FCC), triangular voids can be formed between the spheres. 2. **Counting Triangular Voids**: In a typical close-packed structure, there are 4 triangular voids formed in the arrangement. 3. **Conclusion**: Therefore, this statement is also **false**. ### Step 3: Evaluate Statement S3 **Statement S3**: "In ZnS structure, 2Zn²⁺ and 2S²⁻ ions are present in each unit cell." 1. **Understanding the ZnS Structure**: The zinc blende structure (ZnS) consists of a face-centered cubic lattice of Zn²⁺ ions with S²⁻ ions occupying half of the tetrahedral voids. 2. **Counting Ions in the Unit Cell**: In the ZnS structure, there are actually 4 Zn²⁺ ions and 4 S²⁻ ions per unit cell. 3. **Conclusion**: Thus, this statement is also **false**. ### Final Conclusion All three statements (S1, S2, and S3) are false.

To analyze the statements provided in the question, we will evaluate each statement step by step. ### Step 1: Evaluate Statement S1 **Statement S1**: "Distance between Na⁺ and Cl⁻ in NaCl crystal is more than half of edge length." 1. **Understanding the NaCl Structure**: In a NaCl crystal, the Na⁺ and Cl⁻ ions are arranged in a face-centered cubic (FCC) lattice. The edge length of the unit cell (a) is related to the ionic radii of Na⁺ and Cl⁻. 2. **Distance Calculation**: The distance between Na⁺ and Cl⁻ ions in the NaCl crystal is equal to the sum of their ionic radii (r_Na + r_Cl). 3. **Comparison with Edge Length**: The edge length (a) of the NaCl unit cell is equal to 2(r_Na + r_Cl). Therefore, the distance between Na⁺ and Cl⁻ is actually less than half of the edge length (a/2). ...
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