A scientist attempts to replace a few carbon atoms in 1.0 g of diamond with boron atoms or nitrogen atoms in separate experiments. Which of the following is correct ?

Options

A. The resulting material with B droping will be an n-type semiconductor
B. The resulting material with B droping will be an p-type semiconductor
C. B droping is NOT possible as B cannot from multiple bonds
D. the resulting material with N droping will be a p-type semiconductore

Answer

To solve the question, we need to analyze the effects of doping carbon atoms in diamond with boron and nitrogen atoms. Here’s a step-by-step breakdown of the solution:

### Step 1: Understanding the Doping Elements
1. **Identify the Doping Elements**: The scientist is replacing carbon atoms in diamond with boron and nitrogen.
- Boron (B) is from Group 13 of the periodic table.
- Nitrogen (N) is from Group 15 of the periodic table.

### Step 2: Determine the Type of Semiconductor Formed
2. **Analyze Boron Doping**:
- When carbon is doped with boron, it creates a deficiency of electrons because boron has one less valence electron than carbon.
- This results in the formation of "holes" (positive charge carriers).
- Therefore, doping with boron creates a **p-type semiconductor**.

3. **Analyze Nitrogen Doping**:
- When carbon is doped with nitrogen, nitrogen has one extra valence electron compared to carbon.
- This extra electron contributes to the conduction process, resulting in an increase in negative charge carriers (electrons).
- Thus, doping with nitrogen creates an **n-type semiconductor**.

### Step 3: Evaluate the Statements
4. **Evaluate the Given Statements**:
- **Statement 1**: "The resulting material with boron doping will be an n-type semiconductor."
- This is incorrect; it will be a p-type semiconductor.
- **Statement 2**: "B doping is not possible as we cannot form multiple bonds."
- This is incorrect; boron can indeed be used to dope carbon.
- **Statement 3**: "The resulting material with n doping will be a p-type semiconductor."
- This is also incorrect; it will be an n-type semiconductor.

### Conclusion
5. **Correct Answer**: The correct understanding is that doping with boron leads to a p-type semiconductor, while doping with nitrogen leads to an n-type semiconductor. Therefore, the statements regarding the nature of the semiconductors formed are incorrect.

### Final Answer
The correct conclusion is that:
- Doping with boron results in a **p-type semiconductor**.
- Doping with nitrogen results in an **n-type semiconductor**.