The distance between adjacent, oppositely charged ions is rubidium chloride is `3.285Å`, in potassium chloride is `3.139Å` in sodium bromide is` 2.981Å`. And in potassium bromide is `3.293Å`. The distance between adjacent oppositely charged ions in rubidium bromide is:

Options

A. `3.147 Å`
B. `3.385Å`
C. `3.393 Å`
D. `3.439Å`

Explanation

To find the distance between adjacent oppositely charged ions in rubidium bromide (RbBr), we can use the distances provided for other compounds and apply a mathematical approach. Here’s a step-by-step solution:

### Step 1: Identify the Given Distances
We have the following distances between adjacent oppositely charged ions:
- Rubidium Chloride (RbCl): \(3.285 \, \text{Å}\)
- Potassium Chloride (KCl): \(3.139 \, \text{Å}\)
- Sodium Bromide (NaBr): \(2.981 \, \text{Å}\)
- Potassium Bromide (KBr): \(3.293 \, \text{Å}\)

### Step 2: Set Up the Equation
To find the distance between Rb+ and Br-, we can set up the following equation based on the distances provided:
\[ \text{Distance in RbBr} = \text{Distance in RbCl} + \text{Distance in KBr} - \text{Distance in KCl} \]

### Step 3: Substitute the Values
Now, we substitute the values into the equation:
\[ \text{Distance in RbBr} = 3.285 \, \text{Å} + 3.293 \, \text{Å} - 3.139 \, \text{Å} \]

### Step 4: Perform the Calculation
Now, we perform the calculation step-by-step:
1. Add \(3.285 \, \text{Å}\) and \(3.293 \, \text{Å}\):
\[ 3.285 + 3.293 = 6.578 \, \text{Å} \]
2. Subtract \(3.139 \, \text{Å}\) from \(6.578 \, \text{Å}\):
\[ 6.578 - 3.139 = 3.439 \, \text{Å} \]

### Step 5: Conclusion
Thus, the distance between adjacent oppositely charged ions in rubidium bromide (RbBr) is:
\[ \boxed{3.439 \, \text{Å}} \]

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