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If the tangent at (1,1) on y^2=x(2-x)^2 ...

If the tangent at `(1,1)` on `y^2=x(2-x)^2` meets the curve again at `P ,` then find coordinates of `P`.

Text Solution

Verified by Experts

The correct Answer is:
(i) `(4,(8)/(3)) (ii) (9//4, 3//8) (iii) (1,-1),(-1,-5)`
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