Home
Class 12
MATHS
If ax^(2)+by^(2)=1 cut a'x^(2)+b'y^(2)=1...

If `ax^(2)+by^(2)=1` cut `a'x^(2)+b'y^(2)=1` orthogonally, then

Text Solution

Verified by Experts

The correct Answer is:
`(3)/(sqrt(2))`
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    RESONANCE ENGLISH|Exercise Exersise -1C|4 Videos

  • APPLICATION OF DERIVATIVES

    RESONANCE ENGLISH|Exercise Exersise -1D|11 Videos

  • APPLICATION OF DERIVATIVES

    RESONANCE ENGLISH|Exercise Exersise -1A|5 Videos

  • COMBINATORICS

    RESONANCE ENGLISH|Exercise Exercise-2 (Part-II: Previously Asked Question of RMO)|5 Videos

Similar Questions

Explore conceptually related problems

If 4x^(2)+ py^(2) =45 and x^(2)-4y^(2) =5 cut orthogonally, then the value of p is

If 4x^(2)+ py^(2) =45 and x^(2)-4y^(2) =5 cut orthogonally, then the value of p is

If two curves ax^2 +by^2=1 and a'x^2+b'y^2=1 intersect orthogonally,then show that 1/a-1/b=1/[a']-1/[b']

If the curves 2x^(2)+3y^(2)=6 and ax^(2)+4y^(2)=4 intersect orthogonally, then a =

If a circle passes through the point (1, 1) and cuts the circle x^(2)+y^(2)=1 orthogonally, then the locus of its centre is

If the curves (x^2)/(a^2)+(y^2)/(b^2)=1 and (x^2)/(l^2)-(y^2)/(m^2)=1 cut each other orthogonally then.....

If the curves (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 and (x^(2))/(c^(2))+(y^(2))/(d^(2))=1 intersect orthogonally, then

If a circle passes through the point (a, b) and cuts the circle x^2 + y^2 = 4 orthogonally, then the locus of its centre is (a) 2ax+2by-(a^(2)+b^(2)+4)=0 (b) 2ax+2by-(a^(2)-b^(2)+k^(2))=0 (c) x^(2)+y^(2)-3ax-4by+(a^(2)+b^(2)-k^(2))=0 (d) x^(2)+y^(2)-2ax-3by+(a^(2)-b^(2)-k^(2))=0

If the family of curves y=ax^2+b cuts the family of curves x^2+2y^2-y=a orthogonally, then the value of b = (A) 1 (B) 2/3 (C) 1/8 (D) 1/4

If the curves ay + x^(2) = 7 and y = x^(3) cut orthogonally at (1,1) , then the value of a is