Let f(x) `=x^(2) , x in (-1,2)` Then show that f(x) has exactly one point of local minima but global maximum Is not defined.

Let f(x)=x^(3)-3x^(2)+6 find the point at which f(x) assumes local maximum and local minimum.

Let f(x)=x^(3) find the point at which f(x) assumes local maximum and local minimum.

Let f(x)=sinx-x" on"[0,pi//2] find local maximum and local minimum.

The function f(x)=|x^2-2|/|x^2-4| has, (a) no point of local maxima (b) no point of local minima (c) exactly one point of local minima (d) exactly one point of local maxima

consider f(X) =(1)/(1+|x|)+(1)/(1+|x-1|) Let x_(1) and x_(2) be point wher f(x) attains local minmum and global maximum respectively .If k=f(x_(1))+f(x_(2)) then 6k-9=________.

let f(x)=(x^2-1)^n (x^2+x-1) then f(x) has local minimum at x=1 when

Let f(x)=2sin^(3)x+lamdasin^(2)x,-(pi)/2ltxlt(pi)/2 . If f(x) has exactly one minimum and one maximum, then lamda cannot be equal to

Draw graph of f(x) =x|x-2| and hence find points of local maxima // minima.

Let f(x)=x(x-1)^(2), find the point at which f(x) assumes maximum and minimum.

Let f=NtoN be defined by f(x)=x^(2)+x+1,x inN , then prove that f is one-one but not onto.