Home
Class 12
MATHS
which of the following statement is ...

which of the following statement `is // are ` true ?
(i) f(x) =sin x is increasing in interval `[(-pi)/(2),(pi)/(2)]`
(ii) f(x) = sin x is increasing at all point of the interval `[(-pi)/(2),(pi)/(2)]`
(3) f(x) = sin x is increasing in interval `((-pi)/(2),(pi)/(2)) UU ((3pi)/(2),(5pi)/(2))`
(4) f(x)=sin x is increasing at all point of the interval `((-pi)/(2),(pi)/(2)) UU ((3pi)/(2),(5pi)/(2))`
(5) f(x) = sin x is increasing in intervals `[(-pi)/(2),(pi)/(2)]& [(3pi)/(2),(5pi)/(2)]`

A

all are correct

B

all are false

C

(3) and (4) are correct

D

(1),(4) & (5) are correct

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the statements about the function \( f(x) = \sin x \) are true, we need to analyze the behavior of the sine function over the specified intervals. Here’s a step-by-step solution: ### Step 1: Analyze the function \( f(x) = \sin x \) The sine function is periodic and oscillates between -1 and 1. Its derivative, \( f'(x) = \cos x \), tells us about its increasing and decreasing behavior. ### Step 2: Find the critical points To find where \( f(x) \) is increasing or decreasing, we set the derivative to zero: \[ f'(x) = \cos x = 0 \] This occurs at: \[ x = \frac{\pi}{2} + n\pi \quad (n \in \mathbb{Z}) \] The critical points in the interval \([- \frac{\pi}{2}, \frac{\pi}{2}]\) are \( x = \frac{\pi}{2} \). ### Step 3: Determine the sign of the derivative - In the interval \([- \frac{\pi}{2}, \frac{\pi}{2}]\): - \( f'(x) > 0 \) when \( x \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right) \) - \( f'(x) = 0 \) at \( x = \frac{\pi}{2} \) Thus, \( f(x) = \sin x \) is increasing on the interval \((- \frac{\pi}{2}, \frac{\pi}{2})\). ### Step 4: Analyze the interval \((\frac{3\pi}{2}, \frac{5\pi}{2})\) - In the interval \((\frac{3\pi}{2}, \frac{5\pi}{2})\): - \( f'(x) > 0 \) when \( x \in \left(\frac{3\pi}{2}, \frac{5\pi}{2}\right) \) Thus, \( f(x) = \sin x \) is also increasing on this interval. ### Step 5: Evaluate the statements 1. **Statement (i)**: \( f(x) = \sin x \) is increasing in the interval \([- \frac{\pi}{2}, \frac{\pi}{2}]\) - **True**. 2. **Statement (ii)**: \( f(x) = \sin x \) is increasing at all points of the interval \([- \frac{\pi}{2}, \frac{\pi}{2}]\) - **True**. 3. **Statement (iii)**: \( f(x) = \sin x \) is increasing in the interval \((- \frac{\pi}{2}, \frac{\pi}{2}) \cup (\frac{3\pi}{2}, \frac{5\pi}{2})\) - **True**. 4. **Statement (iv)**: \( f(x) = \sin x \) is increasing at all points in the interval \((- \frac{\pi}{2}, \frac{\pi}{2}) \cup (\frac{3\pi}{2}, \frac{5\pi}{2})\) - **True**. 5. **Statement (v)**: \( f(x) = \sin x \) is increasing in intervals \([- \frac{\pi}{2}, \frac{\pi}{2}]\) & \((\frac{3\pi}{2}, \frac{5\pi}{2})\) - **True**. ### Conclusion All statements (i), (ii), (iii), (iv), and (v) are true.
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    RESONANCE ENGLISH|Exercise Exersise Part II -1E|6 Videos
  • APPLICATION OF DERIVATIVES

    RESONANCE ENGLISH|Exercise Exersise Part II -1F|4 Videos
  • APPLICATION OF DERIVATIVES

    RESONANCE ENGLISH|Exercise Exersise Part II -1C|5 Videos
  • COMBINATORICS

    RESONANCE ENGLISH|Exercise Exercise-2 (Part-II: Previously Asked Question of RMO)|5 Videos

Similar Questions

Explore conceptually related problems

Show that f(x)=sinx is an increasing function on (-pi//2,\ pi//2) .

Function f : [(pi)/(2), (3pi)/(2)] rarr [-1, 1], f(x) = sin x is

Show that f(x)=tanx is an increasing function on (-pi//2,\ pi//2) .

Show that the function f(x)=sin^(4) x+ cos^(4) x (i) is decreasing in the interval [0,pi/4] . (ii) is increasing in the interval [pi/4,pi/2] .

Consider f(x)=sin3x,0<=x<=(pi)/(2), then (a) f(x) is increasing for x in(0,(pi)/(6)) and decreasing for x in((pi)/(6),(pi)/(2)) (b) f(x) is increasing forx in(0,(pi)/(4)) and decreasing for x in((pi)/(4),(pi)/(2)) (c) f(x)

Show that the function f(x) = log (sin x) (i) is strictly increasing in the interval ]0,pi/2[ . (ii) is strictly decreasing in the interval ]pi/2,pi[ .

The range of f(x)=sin^(3)x in domain [-(pi)/(2),(pi)/(2)] is

The minimum value of f(x)= "sin"x, [(-pi)/(2),(pi)/(2)] is

Prove that the function f(x)=cosx is strictly increasing in (pi,\ 2pi)

On the interval [-(pi)/(4) , (pi)/(4)] , the function f (x) = sqrt(1 + sin^(2) x) has a maximum value of