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if f(x) be a twice differentiable funct...

if f(x) be a twice differentiable function such that `f(x) =x^(2) " for " x=1,2,3,` then

A

`f''(x)=2 " "AA x in [1,3]`

B

`f''(x) =2 " ""for some " x in (1,3)`

C

`f''(x) =2 " " AA x in (1,3)`

D

`f'(x) =2x " " AA x in (1,3)`

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The correct Answer is:
To solve the given problem, we need to analyze the function \( f(x) \) which is defined as \( f(x) = x^2 \) for \( x = 1, 2, 3 \). We also know that \( f(x) \) is a twice differentiable function. We will derive the first and second derivatives and check the validity of the given options. ### Step-by-Step Solution: 1. **Understanding the function**: We know that \( f(x) = x^2 \) at the points \( x = 1, 2, 3 \). 2. **Finding the first derivative**: We differentiate \( f(x) \): \[ f'(x) = \frac{d}{dx}(x^2) = 2x \] This derivative is valid for all \( x \), but we will check its behavior specifically at \( x = 1, 2, 3 \). 3. **Finding the second derivative**: We differentiate \( f'(x) \): \[ f''(x) = \frac{d}{dx}(2x) = 2 \] This second derivative is also valid for all \( x \). 4. **Evaluating the derivatives at specific points**: - At \( x = 1 \): \[ f'(1) = 2 \cdot 1 = 2 \] \[ f''(1) = 2 \] - At \( x = 2 \): \[ f'(2) = 2 \cdot 2 = 4 \] \[ f''(2) = 2 \] - At \( x = 3 \): \[ f'(3) = 2 \cdot 3 = 6 \] \[ f''(3) = 2 \] 5. **Analyzing the options**: - **Option 1**: \( f'(x) = 2x \) for all \( x \) in the interval [1, 3]. This is true, but the function is not defined as \( f(x) = x^2 \) for all \( x \) in this interval. Thus, this option is incorrect. - **Option 2**: \( f''(x) = 2 \) for some values of \( x \) in [1, 3]. This is true since \( f''(x) = 2 \) for all \( x \), including the values 1, 2, and 3. This option is correct. - **Option 3**: \( f''(x) = 2 \) for all \( x \) in [1, 3]. This is true, but again, it is not defined for all \( x \) in this interval. Thus, this option is incorrect. - **Option 4**: \( f'(x) = 2x \) for all \( x \) in [1, 3]. This is true, but it is not defined as \( f(x) = x^2 \) for all \( x \) in this interval. Thus, this option is incorrect. ### Conclusion: The only correct option is **Option 2**: \( f''(x) = 2 \) for some values of \( x \) in [1, 3].
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