if A be the area of a triangle, prove that the error in A resulting from small error in the measurement of c is given by `dA=A/4(1/s+1/(s-a)+1/(s-b)-1/(s-c))dc,2s=a+b+c.`

S = 1/2 at^2 where a is a constant. If relative error in measurement of t is y, relative error in measurment of S will be

Using vectors: Prove that if a,b,care the lengths of three sides of a triangle then its area Delta is given by Delta= sqrt(s(s-a)(s-b)(s-c)) where 2s=a+b+c

Statement I If the sides of a triangle are 13, 14 15 then the radius of in circle =4 Statement II In a DeltaABC, Delta = sqrt(s (s-a) (s-b) (s-c)) where s=(a+b+c)/(2) and r =(Delta)/(s)

In any triangle A B C , prove that following: \ \ bcosB+c\ cos\ C="a c o s"(B-C)

If in a triangle ABC, right angled at B, s-a=3, s-c=2, then the values of a and c are respectively

If c^2 = a^2 + b^2, 2s = a + b + c , then 4s(s-a) (s - b)(s-c)

The area of a triangleis computed using the formula S=1/2 bc sin A . If the relative errors made in measuring b,c and calculating S are respectively 0.02,0.01 and 0.13 the approximate error in A when A=pi//6 , is

Statement - I : If two sides of a triangle are 4 and 5, then its area lies in (0, 10] Because : Statement - II : Area of a triangle =1/2a b\ s in C\ a n d\ s in C\ in (0,\ 1] A (b) B (c) C (d) D

If in a triangle ABC, (s-a)(s-b)= s(s-c), then angle C is equal to

The energy of a system as a function of time t is given as E(t) = A^(2)exp(-alphat) , alpha = 0.2 s^(-1) . The measurement of A has an error of 1.25% . If the error In the measurement of time is 1.50% , the percentage error in the value of E(t) at t = 5 s is