Solve `sin^(-1)(x^(2)-2x+1)+cos^(-1)(x^(2)-x)=(pi)/2`

Explanation

To solve the equation \( \sin^{-1}(x^2 - 2x + 1) + \cos^{-1}(x^2 - x) = \frac{\pi}{2} \), we can follow these steps:

### Step 1: Recognize the Identity
We know that:
\[ \sin^{-1}(a) + \cos^{-1}(a) = \frac{\pi}{2} \]
for any \( a \) in the domain of the inverse sine and cosine functions. Therefore, we can set:
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