Home
Class 12
PHYSICS
A series AC circuit has resistance of 4 ...

A series `AC` circuit has resistance of `4 Omega` and a reactance of `3 Omega`.the impedance of the circuit is

A

`5Omega`

B

`7Omega`

C

`12//7Omega`

D

`7//12Omega`

Text Solution

Verified by Experts

The correct Answer is:
A

`Z=sqrt(4^(2)+3^(2))"=5Omega`
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise EXERCISE SECTION A|4 Videos
  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise SECTION B|15 Videos
  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise EXAMPLE|40 Videos
  • ATOMIC PHYSICS

    RESONANCE ENGLISH|Exercise Advanved level problems|17 Videos

Similar Questions

Explore conceptually related problems

A series AC circuit has a resistance of 4 Omega and a reactance of 3 Omega . The impedance of the circuit is

A series AC circuit has a resistance of 4 Omega and a reactance of 3 Omega . The impedance of the circuit is

In L-R circuit, resistance is 8Omega and inductive reactance is 6Omega then impedance is:

An alternating supply of 220 V is applied across a circuit with resistance 22 Omega and impedance 44 Omega . The power dissipated in the circuit is

An AC of frequency f is flowing in a circuit containing a resistance R and capacitance C in series. The impedance of the circuit is equal to

In a series LCR circuit, the total reactance is 4 Omega and resistance is 3 Omega . Its power factor is

A 50 Hz AC signal is applied in a circuit of inductance of (1//pi) H and resistance 2100Omega. The impedance offered by the circuit is

An rms voltage of 110 V is applied across a series circuit having a resistance 11 Omega and an impedance 22 Omega . The power consumed is

The impedance of a series circuit consists of 3 ohm resistance and 4 ohm reactance.The power factor of the circuit is

In a series LCR circuit resistance R = 10Omega and the impedance Z = 10 Omega The phase difference between the current and the voltage is