Home
Class 12
PHYSICS
r.m.s value of current i=3+4 sin (omega ...

`r.m.s` value of current `i=3+4 sin (omega t+pi//3)` is:

A

5A

B

`sqrt17A`

C

`(5)/(sqrt2)A`

D

`(7)/(sqrt2)A`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise SECTION F|7 Videos

  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise PART-III: Match the column|2 Videos

  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise SECTION E:|6 Videos

  • ATOMIC PHYSICS

    RESONANCE ENGLISH|Exercise Advanved level problems|17 Videos

Similar Questions

Explore conceptually related problems

r.m.s. value of current i=3+4sin (omegat+pi//3) is

Find the rms value of current i=I_(m)sin omegat from (i) t=0 "to" t=(pi)/(omega) (ii) t=(pi)/(2omega) "to" t=(3pi)/(2omega)

The average value of current i=I_(m) sin omega t from t=(pi)/(2 omega ) to t=(3 pi)/(2 omega) si how many times of (I_m) ?

The average value of current i=I_(m) sin omega t from t=(pi)/(2 omega ) to t=(3 pi)/(2 omega) si how many times of (I_m) ?

(a) The peak voltag3e of an a.c. supply is 300 V. What is its r.m.s voltages? (b) The r.m.s value of current in an ac circuit is 10 A. What is the peak current ?

Find the rms value of current from t = 0 to t=(2pi)/omega if the current varies as i=I_(m)sin omegat .

Find the rms value of current from t=0 to t= (2pi)/(omega) if the current avries as i=I_(m)sin omegat .

Find the rms value of current from t=0 to t= (2pi)/(omega) if the current avries as i=I_(m)sin omegat .

The average value of alternating current I=I_(0) sin omegat in time interval [0, pi/omega] is

Find the effective value of current. i=2 sin 100 (pi)t + 2 cos (100 pi t + 30^(@)) .

Home
Profile