Home
Class 12
PHYSICS
An inductor X(L) = 2Omega ) , a capacito...

An inductor `X_(L)` = 2`Omega` ) , a capacitor (`X_(C)` = 8`Omega`) and a resistance (R = 8 `Omega` ) are connected in series with an AC source . The voltage output of AC source is given by V = 10 cos(100`pi`t)
The instantaneous potential difference between points A and B, when the applied voltage is 3/5th of the maximum value of applied voltage is

Text Solution

Verified by Experts

The correct Answer is:
48
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise PART III:|15 Videos

  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise PART-IV Comprehension|11 Videos

  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise EXERCISE-16|1 Videos

  • ATOMIC PHYSICS

    RESONANCE ENGLISH|Exercise Advanved level problems|17 Videos

Similar Questions

Explore conceptually related problems

An inductor (L = (1)/(100 pi) H) , a capacitor (C = (1)/(500 pi) F) and a resistance (3 Omega) is connected in series with an AC voltage source as shown in the figure. The voltage of the AC source is given as V = 10 cos(100 pi t) volt. What will be the potential difference between A and B ?

An inductance L , a capacitor of 20mu F and a resistor of 10Omega are connected in series with an AC source of frequency 50 Hz . If the current is in phase with the voltage, then the inductance of the inductor is

A inductor of reactance 1 Omega and a resistor of 2 Omega are connected in series to the terminals of a 6 V (rms) a.c. source. The power dissipated in the circuit is

A inductor of reactance 1 Omega and a resistor of 2 Omega are connected in series to the terminals of a 6 V (rms) a.c. source. The power dissipated in the circuit is

A inductor of reactance 1 Omega and a resistor of 2 Omega are connected in series to the terminals of a 6 V (rms) a.c. source. The power dissipated in the circuit is

If resistance R =100 Omega, inductance L = 12mH and capacitance C=15muF are connected in series to an AC sources, then at resonance the impedance of circuit is

A resistor and a capacitor are connected in series with an a.c. source. If the potential drop across the capacitor is 5 V and that across resistor is 12 V, applied voltage is

A 0.21 H inductor and a 12 Omega resistance are connected in series to a 220 V, 50 Hz ac source. the phase angle between the current and the source voltage is

A 0.01 H inductor and sqrt(3)pi Omega resistance are connected in series with a 220 V, 50 Hz AC source. The phase difference between the current and emf is

An inductor 200 mH, capacitor 500mu F and resistor 10 Omega are connected in series with a 100 V variable frequency ac source. What is the frequency at which the power factor of the circuit is unity?