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A parallel - plate capacitor of plate ar...

A parallel - plate capacitor of plate area `A` and plate separation d is charged to a potential difference `V` and then the battery is disconnected . `A` slab of dielectric constant `K` is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.

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The correct Answer is:
`(in_(0)AV^(2))/(2d)((1)/(2k)-1)`
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RESONANCE ENGLISH-CAPACITANCE-Exercise - 1
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  2. Two parallel plate capacitors of capacitance C each are connected in s...

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  3. A parallel - plate capacitor of plate area A and plate separation d is...

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  4. Consider the situation shown in figure .The width of each plate is b.T...

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  5. The separation between the plates of a charged parallel-plate capacito...

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  6. The plates of the parallel plate capacitor have plate area A and are c...

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  7. A parallel-plate capacitor is filled with a dielectric up to one-half ...

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  8. A positive charge q is given to each place of a parallel plate air cap...

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  9. The radii of two metallic spheres are 5 cm and 10 cm and both carry ...

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  10. Two insulated charged spheres of radii R(1) and R(2) having charges Q(...

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  11. A parallel plate capacitor is charged up to a potential of 300 volts....

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  12. A parallel plate capacitor is charged up to a potential of 300 volts....

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  13. A parallel plate capacitor is charged up to a potential of 300 volts....

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  14. A parallel plate capacitor is charged up to a potential of 300 volts....

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  15. A parallel plate capacitor is charged and then isolated. On increasing...

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  16. A parallel plate capacitor is charged and the charging battery is then...

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  17. The work done against electric in increasing the potential difference ...

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  18. The magnitude of charge in steady state on either of the plates of c...

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  19. The plate separation in a parallel plate condenser and plate area is A...

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  20. In the adjoining diagram, the condenser C will be fully charged to pot...

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