Home
Class 12
PHYSICS
The plates of the parallel plate capacit...

The plates of the parallel plate capacitor have plate area A and are clamped in the laboratory as shown in figure. The dielectric slab of mass m, length 2l and width 2l is released from rest with length l inside the capacitor. Neglecting any effect of friction or gravity, show that the slab will execute periodic motion and find its time period. (plates of capacitor are square plates of side 2l)

Text Solution

Verified by Experts

The correct Answer is:
`4.sqrt((2bm)/(in_(0)V^(2)(K-1)))`
Promotional Banner

Topper's Solved these Questions

  • CAPACITANCE

    RESONANCE ENGLISH|Exercise Exercise - 2|74 Videos
  • CAPACITANCE

    RESONANCE ENGLISH|Exercise Exercise - 3|26 Videos
  • CAPACITANCE

    RESONANCE ENGLISH|Exercise Miscellaneous Solved Example|3 Videos
  • ATOMIC PHYSICS

    RESONANCE ENGLISH|Exercise Advanved level problems|17 Videos
  • COMMUNICATION SYSTEMS

    RESONANCE ENGLISH|Exercise Exercise 3|13 Videos

Similar Questions

Explore conceptually related problems

Consider the situation shown in figure. The plates of the capacitor have plate area A and are clamped in the laboratory, the dielectric slab is released from rest with a length a inside the capacitor. Neglecting any effect of friction or gravity . Show that the slab will execute periodic motion and find its time period.

If the plates of a parallel plate capacitor are not equal in area, then

A copper plate of thickness b is placed inside a parallel plate capacitor of plate distance d and area A as shown in figure. The capacitance of capacitor is

A parallel plate capacitor, with plate area A and plate separation d, is filled with a dielectric slabe as shown. What is the capacitance of the arrangement ?

The capacitance of a parallel plate capacitor with plate area A and separation d is C . The space between the plates in filled with two wedges of dielectric constants K_(1) and K_(2) respectively. Find the capacitance of resulting capacitor.

In a parallel-plate capacitor, the region between the plates is filled by a dielectric slab. The capacitor is connected to a cell and the slab is taken out. Then

A parallel plate capacitor of capacitance C (without dielectric) is filled by dielectric slabs as shown in figure. Then the new capacitance of the capacitor is

A parallel plate capacitor is connected across a battery. Now, keeping the battery connected, a dielectric slab is inserted between the plates. In the process,

Parallel Plate Capacitors with and without Dielectric

The space between the plates of a parallel plate capacitor of capacitance C is filled with three dielectric slabs of identical size as shown in figure. If the dielectric constants of the three slabs are K_1 , K_2 and K_3 find the new capacitance.

RESONANCE ENGLISH-CAPACITANCE-Exercise - 1
  1. Consider the situation shown in figure .The width of each plate is b.T...

    Text Solution

    |

  2. The separation between the plates of a charged parallel-plate capacito...

    Text Solution

    |

  3. The plates of the parallel plate capacitor have plate area A and are c...

    Text Solution

    |

  4. A parallel-plate capacitor is filled with a dielectric up to one-half ...

    Text Solution

    |

  5. A positive charge q is given to each place of a parallel plate air cap...

    Text Solution

    |

  6. The radii of two metallic spheres are 5 cm and 10 cm and both carry ...

    Text Solution

    |

  7. Two insulated charged spheres of radii R(1) and R(2) having charges Q(...

    Text Solution

    |

  8. A parallel plate capacitor is charged up to a potential of 300 volts....

    Text Solution

    |

  9. A parallel plate capacitor is charged up to a potential of 300 volts....

    Text Solution

    |

  10. A parallel plate capacitor is charged up to a potential of 300 volts....

    Text Solution

    |

  11. A parallel plate capacitor is charged up to a potential of 300 volts....

    Text Solution

    |

  12. A parallel plate capacitor is charged and then isolated. On increasing...

    Text Solution

    |

  13. A parallel plate capacitor is charged and the charging battery is then...

    Text Solution

    |

  14. The work done against electric in increasing the potential difference ...

    Text Solution

    |

  15. The magnitude of charge in steady state on either of the plates of c...

    Text Solution

    |

  16. The plate separation in a parallel plate condenser and plate area is A...

    Text Solution

    |

  17. In the adjoining diagram, the condenser C will be fully charged to pot...

    Text Solution

    |

  18. A parallel plate capacitor of capacitance C is connected to a battery ...

    Text Solution

    |

  19. A generator has an EMF of 440 V and internal resistance of 400 ohm . I...

    Text Solution

    |

  20. In the adjoining circuit, the capacity between the points A and B will...

    Text Solution

    |