A generator has an EMF of 440 V and internal resistance of 400 ohm . Its terminals are connected to a load of 4000 ohm , the voltage across the load is

Options

A. a) 220 V
B. b) 440 V
C. c) 200 V
D. d) 400 V

Answer

To solve the problem, we need to find the voltage across the load connected to a generator with a given EMF and internal resistance. Here’s a step-by-step solution:

### Step 1: Identify the given values
- EMF (E) of the generator = 440 V
- Internal resistance (r) of the generator = 400 ohm
- Load resistance (R_L) = 4000 ohm

### Step 2: Calculate the total resistance in the circuit
The total resistance (R_total) in the circuit is the sum of the internal resistance of the generator and the load resistance:
\[ R_{total} = r + R_L \]
\[ R_{total} = 400 \, \Omega + 4000 \, \Omega \]
\[ R_{total} = 4400 \, \Omega \]

### Step 3: Calculate the current flowing through the circuit
Using Ohm's law, the current (I) flowing through the circuit can be calculated as:
\[ I = \frac{E}{R_{total}} \]
\[ I = \frac{440 \, V}{4400 \, \Omega} \]
\[ I = 0.1 \, A \]

### Step 4: Calculate the voltage across the load resistance
The voltage across the load resistance (V_L) can be calculated using Ohm's law:
\[ V_L = I \times R_L \]
\[ V_L = 0.1 \, A \times 4000 \, \Omega \]
\[ V_L = 400 \, V \]

### Conclusion
The voltage across the load is **400 V**.

### Final Answer
The correct option is **D) 400 V**.

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