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A battery charges a parallel plate capac...

A battery charges a parallel plate capacitor separated by distance (d) so that the energy `(V_(0))` is stored in the system. A slab of dielectric constant (K) and thickness (d) is then introduced between the plates of capacitor. The new energy of the system is given by

A

`KU_(0)`

B

`K^(2)U_(0)`

C

`(U_(0))/(K)`

D

`(U_(0))/(K^(2))`

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The correct Answer is:
A
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RESONANCE ENGLISH-CAPACITANCE-Exercise - 1
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  4. An uncharged capacitor of capacitance 100 mu F is connected to a bat...

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  5. An uncharged capacitor of capacitance 100 mu F is connected to a bat...

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  6. The charge on each of the capacitors 0.16 ms after the switch S is c...

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  7. The plates of a capacitor of capacitance 10(mu)F,charged to 60(mu)C,ar...

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  8. The plates of a capacitor of capacitance 10(mu)F,charged to 60(mu)C,ar...

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  9. The plates of a capacitor of capacitance 10(mu)F,charged to 60(mu)C,ar...

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  10. The switch S shown in figure is kept closed for a long time and is the...

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  11. The distance between plates of a parallel plate capacitor is d . Anoth...

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  12. On placing dielectric slab between the plates of an isolated charged c...

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  13. The effective capacitance of the system in adjoining figure will be -

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  14. In the adjoining diagram two geometrically identical capacitors A an...

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  15. A parallel plate condenser is connected to a battery of e.m.f. 4 volt....

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  16. In the above problem, if the battery is disconnected before inserting ...

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  17. A battery charges a parallel plate capacitor separated by distance (d)...

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  18. In the above problem, if the battery is disconnected before inserting ...

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  19. The circuit involves two ideal cells connected to a 1 mu F capacitor ...

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  20. In each situation of column-I, a circuit involving two non-ideal cells...

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