Home
Class 12
PHYSICS
A parallel plate capacitor of plate area...

A parallel plate capacitor of plate area a and plate separation d is charged to potential difference V and then the battery is disconnected. A slab of dielectric costant K is then inserted between the plates of the capacitor so as to fill the space between the plates. If Q,E,and W denote, respectively, the magnitude of charge on each plate, the electric field between the plates (after the slab is inserted) and work done on the system, in question, in the process of inserting the slab, then

A

`q=(in_(0)AV)/(d)`

B

`Q=(in_(0)KAV)/(d)`

C

`E=(V)/(Kd)`

D

`W=(in_(0)AV^(2))/(2d)(1-(1)/(K))`

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
Promotional Banner

Topper's Solved these Questions

  • CAPACITANCE

    RESONANCE ENGLISH|Exercise Exercise - 3|26 Videos
  • CAPACITANCE

    RESONANCE ENGLISH|Exercise High Level Problems|16 Videos
  • CAPACITANCE

    RESONANCE ENGLISH|Exercise Exercise - 1|79 Videos
  • ATOMIC PHYSICS

    RESONANCE ENGLISH|Exercise Advanved level problems|17 Videos
  • COMMUNICATION SYSTEMS

    RESONANCE ENGLISH|Exercise Exercise 3|13 Videos

Similar Questions

Explore conceptually related problems

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.

In a parallel-plate capacitor of plate area A , plate separation d and charge Q the force of attraction between the plates is F .

A dielectric slab is inserted between the plates of an isolated capacitor. The force between the plates will

Figure shows a parallel plate capacitor with plate area A and plate separation d . A potential difference is being applied between the plates. The battery is then disconnected and a dielectric slab of dieletric constant K is placed in between the plates of the capacitor as shown. The electric field in the gaps between the plates and the electric slab will be

Figue shows a parallel plate capacitor with plate area A and plate separation d . A potential difference is being applied between the plates. The battery is then disconnected and a dielectric slab of dieletric constant K is placed in between the plates of the capacitor as shown. The electric field in the dielectric slab is

A dielectric slab is inserted between the plates of an isolatted capacitoe. The forcebetween the plates will

A parallel plate capacitor of plate area A and plates separation distance d is charged by applying a potential V_(0) between the plates. The dielectric constant of the medium between the plates is K. What is the uniform electric field E between the plates of the capacitor ?

A pararllel plate capacitor has plates of area A and separation d and is charged to potential diference V . The charging battery is then disconnected and the plates are pulle apart until their separation is 2d . What is the work required to separate the plates?

A parallel plate capacitor each with plate area A and separation ‘d’ is charged to a potential difference V. The battery used to charge it is then disconnected. A dielectric slab of thickness d and dielectric constant K is now placed between the plates. What change if any, will take place in (i) charge on the plates (ii) electric field intensity between the plates, (iii) capacitance of the capacitor Justify your answer in each case

A parallel plate capacitor, with plate area A and plate separation d, is filled with a dielectric slabe as shown. What is the capacitance of the arrangement ?

RESONANCE ENGLISH-CAPACITANCE-Exercise - 2
  1. In the adjoining diagram all the capacitors are initially uncharged, ...

    Text Solution

    |

  2. In the circuit shown in figure the switch S is closed at t = 0. A lo...

    Text Solution

    |

  3. When a charged capacitor is connected with an uncharged capacitor , t...

    Text Solution

    |

  4. In the circuit shown in figure. Each capacitor has a capacitance C. Th...

    Text Solution

    |

  5. Two similar condensers are connected in parallel and are charged to...

    Text Solution

    |

  6. We have a combination as shown in following figure. Choose the corre...

    Text Solution

    |

  7. The charge across the capacitor in two different RC circuit 1 and 2 ar...

    Text Solution

    |

  8. The instantaneous charge on capacitor in two discharging RC circuils...

    Text Solution

    |

  9. Capacitor C(1) of capacitance 1 muF and capacitor C(2) of capacitance ...

    Text Solution

    |

  10. The terminals of a battery of emf V are connected to the two plates of...

    Text Solution

    |

  11. A parallel plate capacitor of plate area a and plate separation d is c...

    Text Solution

    |

  12. The plates of a parallel plate capacitor with no dielectric are connec...

    Text Solution

    |

  13. A parallel plate capacitor is charged and then the battery is disconne...

    Text Solution

    |

  14. A parallel plate air capacitor is connected to a battery. The quantiti...

    Text Solution

    |

  15. Capacitor C(3) in the circuit is a veriable capacitor (its capacitance...

    Text Solution

    |

  16. Capacitor C(3) in the circuit is a variable capacitor (its capacitance...

    Text Solution

    |

  17. Capacitor C(3) in the circuit is a variable capacitor (its capacitance...

    Text Solution

    |

  18. In the shown circuit involving a resistance Romega, capacitor of capac...

    Text Solution

    |

  19. In the shown circuit involving a resistance Romega, capacitor of capac...

    Text Solution

    |

  20. In the shown circuit involving a resistance Romega, capacitor of capac...

    Text Solution

    |