A parallel plate capacitor has a dielectric slab of dielectric constant K between its plates that covers `1//3` of the area of its plates, as shown in the figure. The total capacitance of the capacitor is C while that of the portion with dielectric in between is `C_(1)`. When the capacitor is charged, the plate area covered by the dielectric gets charge `Q_1` and the rest of the area gets charge `Q_(2)`. The electric field in the dielectric is `E_(1)` that in the other portion is `E_(2)`. Choose the correct option/options, ignoring edge effects.

Options

A. `(E_(1))/(E_(2))=1`
B. `(E_(1))/(E_(2))=(1)/(K)`
C. `(Q_(1))/(Q_(2))=(3)/(K)`
D. `(C)/(C_(1))=(2+K)/(K)`

Answer

A, D