capacitance of a parallel plate capacitor with plate area A and separation d, is C. The space between the plates is filled with two wedges of dielectric constants `K_(1) and K_(2)` respectively (figure). The capacitance of resulting capacitor is ___________.

Answer

`C_(R)=(CK_(1)K_(2))/(K_(2)-K_(1))l n (K_(2))/(K_(1)) "where " C=(in_(0)A)/(d)`