Find free electrons per unit volume in a wire of density `10^(4)kg//m^(3)`, atomic mass number 100 and number of free electron per atom is one.

Explanation

To find the number of free electrons per unit volume in a wire with a given density, atomic mass, and number of free electrons per atom, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Given Values:**
- Density of the wire, \( \rho = 10^4 \, \text{kg/m}^3 \)
- Atomic mass number, \( A = 100 \)
- Number of free electrons per atom, \( n_e = 1 \)
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