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The wire is stretched to increase the le...

The wire is stretched to increase the length by 1%. Find the percentage change in the resistance.

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As we known that `therefore" R"=(pl)/A`
`(DeltaR)/R=(Deltal)/rho+(Deltal)/l-(DeltaA)/A" and "(Deltal)/l=-(DeltaA)/A`
`(DeltaR)/R=O+1+1=2`
Hence percentage increase in the Resistance = 2%
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