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What shunt resistance is required to mak...

What shunt resistance is required to make the 1 mA, `20Omega` galvanometer into an ammeter with a range of O to 50 mA?

Text Solution

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The correct Answer is:
`S=20/49=0.408Omega`
`i_(g)R_(g)=(i-i_(g))S`
`i_(g)=1.0xx10^(-3)A, G=20Omega`
`i=50xx10^(-3)A`
`S=(i_(g)R_(g))/(i-V_(g))=(1xx10^(-3)xx20)/(49xx10^(-3))=0.408Omega`
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