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How can we make a galvanometer with G = ...

How can we make a galvanometer with G = 20`Omega` and `i`=1mA into a voltmeter with a maximum range of 10 V?

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The correct Answer is:
A resistance of `9980Omega` is to be connected in series with the galvanometer.
`v=i_(g)Rs+i_(g)R_(g)`
`10=1xx10^(-3)xxR_(s)+1xx10^(-3)xx20`
`Rs=(10-0.02)/(1xx10^(-3))=9.98/10^(-3)=9980Omega`
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