A battery of emf `1.4 V` and internal resistance `2 Omega` is connected to a resistor of `100 omega` resistance through an ammeter. This resistance of the ammeter is `4//3 Omega`. A voltmeter has also been connected to find the potential difference across the resistor.
a. Draw the circuit diagram.
b. The ammeter reads `0.02 A`. What is the resistance of the voltmeter?
c. The voltmeter reads `1.1 V`. What is the error in the reading?

Answer

(i) `(##RES_PHY_CE_E01_041_A01##)`
(ii) `200 Omega`
(iii) `1.1-4/3=-0.23 V`