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A 50 W bulb is in series with a room hea...

A 50 W bulb is in series with a room heater and the combination is conneted across the mains. To get max, heater output, the 50 W bulb should be replaced by :

A

25 W

B

10 W

C

100 W

D

200 W

Text Solution

Verified by Experts

The correct Answer is:
D
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RESONANCE ENGLISH-CURRENT ELECTRICITY-Exercise-1 (Part-2)
  1. A wire of resistance 0.1 cm^(-1) bent to form a square ABCD of side 10...

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  2. In the circuit shown in Fig. 7.39, the heat produced in the 5 Omega re...

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  3. A 50 W bulb is in series with a room heater and the combination is con...

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  4. The equivalent resistance between the points A and B is

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  5. A battery of internal resistance 4 Omega is connected to he network of...

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  6. In these circuits all the batteries are indentical and have negllgible...

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  7. Two nonideal batteries are connected in parallel. Consider the followi...

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  8. Twelve cells each having the same emf are connected in series and are ...

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  9. Two cells of e.m.f. 10V & 15V are connected in parallel to each other ...

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  10. N sources of current with different emf's are connected as shown in Fi...

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  11. The reading of voltmeter is

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  12. The length of a wire of a potentiometer is 100 cm, and the emf of its ...

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  13. The current through the ammeter shown in figure is 1 A. If each of the...

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  14. The ammeter shown in figure consists of a 480 Omega coil connected in ...

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  15. A galvanometer, together with an unknown resistance in series, is conn...

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  16. A potentiometer wire of length 100cm has a resistance of 10Omega. It i...

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  17. The potentiometer wire AB shown in figure is 50cm long.When AD=30cm, n...

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  18. The current in a conductor and the potential difference across its end...

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  19. In this given circuit, no current is passing through the galvanometer....

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  20. In the circuit PneR, the reading of the galvanometer is same with swit...

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