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The length of a wire of a potentiometer ...

The length of a wire of a potentiometer is 100 cm, and the emf of its cell is E volt. It is employed to measure the emf of a battery whose internal resistance is `0.5Omega`. If the balance point is obtained at l = 30 cm from the positive end, the emf of the battery is

A

`(30E)/(100)`

B

`(30E)/(100.5)`

C

`(30E)/((100-0.5))`

D

`(30(E-0.5i))/(100),(30(E-0.5))/(100)` where I is the current in the potentiometer

Text Solution

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The correct Answer is:
A
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