Home
Class 12
PHYSICS
A simple pendulum with a bob of mass m a...

A simple pendulum with a bob of mass m and a conducting wire of length L, swings under gravity with an angular amplitude `2theta`. If the horizontal component of the earth's magnetic field perpendicular to the plane of motion of the pendulum is B, then the maximum emf induced across the pendulum is

Text Solution

Verified by Experts

The correct Answer is:
`Bl sqrt(gl) sin (theta)/(2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A simple pendulum with bob of mass m and conducting wire of length L swings under gravity through an angle 2theta . The earth's magnetic field component in the direction perpendicular to swing is B. The maximum potential difference induced across the pendulum is

A simple pendulum with bob of mass m and conducting wire of length L swings under gravity through an angle 2 theta . The earth's magnetic field component in the direction perpendicular to swing is B . Maximum potential difference induced across the pendulum is

A simple pendulum with charge bob is oscillating as shown in the figure. Time period of oscillation is T and angular ampliltude is theta . If a uniform magnetic field perpendicular to the plane of oscillation is switched on, then

A simple pendulum with a bob of mass m swings with an angular amplitude of 40^@ . When its angular displacement is 20^@ , the tension in the string is greater than mg cos 20^@

A simple pendulum of length 1 m with a bob of mass m swings with an angular amplitude 30^(@) . Then (g= 9.8m//s^(2)

A simple pendulum has a bob of mass m and swings with an angular amplitude phi . The tension in thread is T . At a certain time the string makes an angle theta with the vertical (theta le phi)

A simple pendulum with a bob of mass m swings with an angular amplitude of 40^@ . When its angular displacement is 20^@ , the tension in the string is greater than mg cos 20^@ true false

A vertical rod of length l is moved with constant velocity v towards east. The vertical component of earth magnetic field is B and angle of dip is theta . The induced e.m.f. in the rod is

At a perpendicular place on the earth, the horizontal component of earth's magnetic field of B, and the angle of dip is theta . A striaght meridian and is moved horizontally perpendicular to its length with a velocity v. The emf induced across the rod is

A semicircular conducting wire of radius a is moving perpendicular to a uniform magnetic field B with speed √2 v as shown in the figure.The emf induced across the wire Is