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A closed coil having 100 turns is rotate...

A closed coil having 100 turns is rotated in a uniform magnetic field `B = 4.0 X 10^(-4)` T about a diameter which is perpendicular to the field. The angular velocity of rotation is 300 revolutions per minute. The area of the coil is `25 cm^2` and its resistance is `4.0 Omega.` Find (a) the average emf developed in the half a turn form a position where the coil is perpendicular to the magnetic field, (b) the average emf in a full turn and (c) the net charge displaced in part (a).

Text Solution

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The correct Answer is:
(a) ` 2.0xx10^(-3) V` (b) zero (c ) `50 muC` (d) `pixx10^(-3)sin(10 pi t)` ( e) `pimV` (f) `(pi^(2))/(2)xx10^(-6)V`
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