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The circuit shown in figure is in the st...

The circuit shown in figure is in the steady state with switch `S_(1)` closed. At t=0, `S_(1)` is opened and switch `S_(2)` is closed.

Find the first instant t, when energy in inductor becomes one third of that in capacitor

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The correct Answer is:
`(pixx10^(-5))/(3) sec. `
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