Find out electric field intensity at point A (0, 1m, 2m) due to a point charge `-20 muC` situated at point `B (sqrt(2)m, 0, 1m)`.

Explanation

To find the electric field intensity at point A (0, 1m, 2m) due to a point charge of \(-20 \mu C\) located at point B \((\sqrt{2} m, 0, 1 m)\), we can follow these steps:

### Step 1: Identify the Charge and its Position
We have a point charge \(Q = -20 \mu C = -20 \times 10^{-6} C\) located at point B with coordinates \((\sqrt{2}, 0, 1)\).

### Step 2: Identify the Point of Interest
The point A where we want to find the electric field intensity has coordinates \((0, 1, 2)\).

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