Find out following

(i) `V_(A)-V_(B)` (ii) `V_(B)-V_(C)` (iii) `V_(C)-V_(A)` (iv) `V_(D)-V_(C)`
(v) `V_(A)-V_(D)` (vi) Arrange the order of potential for points A, B, C and D.

Explanation

(i) `|DeltaV_(AB)|=Ed=20xx2xx10^(-2)=0.4` So, `V_(A)-V_(B)=0.4 V`
because in the direction of electric field potential always decreases.
(ii) `|DeltaV_(BC)|=Ed=20xx2xx10^(-2)=0.4` so, `V_(B)-V_(C)=0.4 V`
(iii) `|DeltaV_(CA)|=Ed=20xx4xx10^(-2)=0.8` so, `V_(C)-V_(A)=-0.8 V`
because In the direction of electric field potential always decreases.
(iv) `|DeltaV_(DC)|=Ed=20xx0=0` so, `V_(D)-V_(C)=0`
because the effective distance D and C is zero.
(v) `|DeltaV_(AD)|=Ed=20xx4xx10^(-2)=0.8` so, `V_(A)-V_(D)=0.8 V`
because In the direction of electric field potential always decreases.
(vi) The order of potential is : `V_(A) gt V_(B) gt V_(C)=V_(D)`.