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Two charges particles each having equal charges `2 xx 10^(-5) C` are brought from infinity to within a separation of 10 cm. Calculate the increase in potential energy during the process and the work required for this purpose.

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To solve the problem, we need to calculate the increase in potential energy when two charges are brought from infinity to a separation of 10 cm. Here are the steps to derive the solution: ### Step 1: Understand the given data We have two charges, each with a charge \( Q = 2 \times 10^{-5} \, C \), and they are separated by a distance \( r = 10 \, cm = 10 \times 10^{-2} \, m \). ### Step 2: Write the formula for potential energy The potential energy \( U \) between two point charges is given by the formula: \[ ...
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RESONANCE ENGLISH-ELECTROSTATICS-HLP
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  18. The potential difference between two large parallel plates is varied a...

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  19. Four point charges +8muC-1muC,-1muC and +8muC are fixed at the points ...

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  20. A small ball of mass 2 xx 10^-3 kg, having a charge 1 mu C, is suspend...

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