`V=x^(2)+y`. Find `vec(E)`.

Explanation

To find the electric field \(\vec{E}\) from the given potential \(V = x^2 + y\), we will follow these steps:

### Step 1: Understand the relationship between electric field and potential
The electric field \(\vec{E}\) is related to the electric potential \(V\) by the equation:
\[ \vec{E} = -\nabla V \]
where \(\nabla\) (del operator) is defined as:
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